Splines Design of the Friction Clutch Disc
Given:
D= 25 mm, d= 22 mm, nsp = 24 spline, Tc = 240 N m, SF = 10
Required:
rm = ? mm, h = ? mm, b= ? mm, F = ?
N
Solution:
rm = (D+d)/4 =
h = (D-d)/2 =
b = p D/(2 nsp) =
F= Tc*1000/rm =
A- Require: Steel
No.
Given: |
Tc = 240 N m, L= 25 mm |
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Stress: |
ts |
sbearing |
sb |
Allowable stress |
=F/(nsp As) =F/(nsp b L)
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=F/(nsp Abearing) =F/(nsp h L) |
=M y /I |
Ultimate stress |
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Steel |
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B- Required: Clutch torque Capacity (Tc)
Given: |
Steel = EN3, L=25 mm |
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Ultimate Stress: |
ts = |
sbearing = |
sb =
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Allowable Stress |
(ts)all =
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(sbearing)all = |
(st)all = |
Force (F) |
F=(ts)all nsp b L
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F=(sbearing)all nsp h L |
F=( (st)all nsp L b2) / (3h) |
Torque Capacity (Tc) |
Tc =F rm /1000
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Tc =F rm /1000
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Tc =F rm /1000
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Tc (N m) |
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C- Required: Splines length (L)
Given: |
Steel = EN3, Tc=200 +(student No.- 1) x 3 = = N m |
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Ultimate Stress: |
ts |
sbearing |
sb
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Allowable Stress |
(ts)all =
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(sbearing)all = |
(st)all = |
Spline force (F)
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F = Tc x 1000 / rm = |
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Splines Length (L) |
L=F/(nsp b (ts)all )
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L=F/(nsp h (sbearing)all) |
L=3 F h/(nsp b2 (st)all)
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L (mm) |
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